[Getdp] GetDP - diode as non-linear resistant
A.Eckert at eunda.ch
A.Eckert at eunda.ch
Tue Apr 23 09:00:52 CEST 2019
Hi Ruth,
thank you very much. That indeed helped a lot.
My idea was to us an e-function, or an inverse e-function respectively, to
approximate the two axis of an ideal diode and keep the function
continuously differentiable.
Resistance[Region[{R_DIODE_1}]] = 1.0 / (Exp[$1]);
By replacing that line through your resistance definition
(Resistance[Region[{R_DIODE_1}]] = (($1 >= 0)? Ron : Roff) ;)
everything works perfectly. I can't tell you, why my original idea doesn't
work.
Thank you.
"Ruth Vazquez Sabariego" <ruth.sabariego at kuleuven.be> am 18.04.2019
15:33:37
Von:
"Ruth Vazquez Sabariego" <ruth.sabariego at kuleuven.be>
An:
"a.eckert at e-und-a.ch" <a.eckert at e-und-a.ch>
Cc:
"getdp at onelab.info" <getdp at onelab.info>
Date:
18.04.2019 15:33 CEDT
Betreff:
Re: [Getdp] GetDP - diode as non-linear resistant
Hi Andreas,
As you have done, you must define:
- dummy regions for the diodes and include them in Diode_Cir;
- a resistance function that depends on the current {Iz}
GlobalTerm { NeverDt[ Resistance[{Iz}] * Dof{Iz} , {Iz} ]; In Diode_Cir; }
or the voltage (what you have done)
GlobalTerm { NeverDt[ Resistance[{Uz}] * Dof{Iz} , {Iz} ]; In Diode_Cir; }
I’ve done it for the case with current:
Ron = 1e-1; // small resistance (diode in state 'on')
Roff = 1e5 ; // big resistance (diode in state 'off')
Resistance[Diode_Cir] = (($1 >= 0)? Ron : Roff) ;
In this case, the voltage would be
UR[Diode_Cir] = Resistance[$1] * $1 ;
In your case, the function for the resistance should be modified.
After that you need to define the circuit with your diodes. For instance
for a single bridge rectifier:
{ Name ElectricalCircuit ; Type Network ;
Case Circuit {
{ Region Input ; Branch {700, 800} ; }
// diodes
{ Region D1 ; Branch {800, 1} ; }
{ Region D2 ; Branch {700, 1} ; }
{ Region D3 ; Branch {999, 800} ; }
{ Region D4 ; Branch {999, 700} ; }
{ Region Crec ; Branch {2, 999}; }
{ Region Rload; Branch {2, 999}; }
// FE coil on DC side
{ Region Inductor ; Branch {1, 2} ; }
}
}
Hope that helps,
Ruth
—
Prof. Ruth V. Sabariego
KU Leuven
Dept. Electrical Engineering ESAT/Electa, EnergyVille
http://www.esat.kuleuven.be/electa
http://www.energyville.be
Free software: http://gmsh.info | http://getdp.info | http://onelab.info
On 17 Apr 2019, at 09:31, A.Eckert at eunda.ch wrote:
Hello everyone
I currently try enlarge the machine model to include external connections.
On of the aims is to model a 3-phased diode rectifier (B6-Bridge) which
uses 6 diodes to rectify the incoming waveforms.
In the example file Lib_Magnetodynamics2D_av_Cir.pro (
https://gitlab.onelab.info/getdp/getdp/blob/master/templates/Lib_Magnetodynamics2D_av_Cir.pro
), there's a hint/comment to use nonlinear resistors to simulate diodes.
Unfortunately I coudln't find an exact example how to implement it.
Following three lines are basically those related to the diodes out of the
above example:
Diode_Cir = Region[{}] ;
GlobalTerm { NeverDt[ Dof{Uz} , {Iz} ]; In Diode_Cir; }
GlobalTerm { NeverDt[ Resistance[{Uz}] * Dof{Iz} , {Iz} ]; In Diode_Cir; }
According to my understanding, the definition of such a resistance is
missing. I simplified the example to one diode.
I added the regions and allocated it to the Diode_Cir.
R_DIODE_1_A0 = Region[{1000012}];
Diode_Cir += Region[{R_DIODE_1_A0}];
In the last step, I set the dynamic resistance. In that case it's just the
input voltage.
Resistance[Region[{R_DIODE_1_A0}]] = $1
The program itself successfully finishes. But basically all values are
-nan, so something runs badly wrong. When I replace $1 in the line above,
through a fix number (e.g. 10 ), the program behaves as it should.
So there's probably still a mistake in the dynamic resistance calculation.
Any help is highly appreciated. Thank you very much.
Mit freundlichen Grüssen
Andreas Eckert
Forschung und Entwicklung / Research and Development
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